Equation 1

Expand the following: $$\begin{array}{rl}\Sigma F_{AX}=0=& F_T\ast h-mg\ast \frac{l}{2}\ast cos(\alpha )-Mg\ast l\ast cos(\alpha )=0\\ & F_T\ast h=mg\ast \frac{l}{2}\ast cos(\alpha )+Mg\ast l\ast cos(\alpha )\\ & F_T=\frac{mg\ast \frac{l}{2}\ast cos(\alpha )+Mg\ast l\ast cos(\alpha )}{h}\end{array}$$

1. Firstly, we assemble the equation to discover the tension force.
2. Secondly, we pass to the other side the terms of the masses.
3. Finally, we pass the height (h) to the other side so is dividing the other terms.