Expand the following: \begin{align} ΣF_{AX}=0 =&\cssId{Step1}{F_T*h-mg*\frac{l}{2}*cos(α)-Mg*l*cos(α)=0}\\[3px] &\cssId{Step2}{F_T*h=mg*\frac{l}{2}*cos(α)+Mg*l*cos(α)}\\[3px] &\cssId{Step3}{F_T=\frac{mg*\frac{l}{2}*cos(α)+Mg*l*cos(α)}{h}}\\[3px] \end{align}

- Firstly, we assemble the equation to discover the tension force.
- Secondly, we pass to the other side the terms of the masses.
- Finally, we pass the height (h) to the other side so is dividing the other terms.